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The equilibrium constant for the formation of ammonia from nitrogen and hydrogen is 1.6 x 102. What is the form of the equilibrium constant?


. [NH3]2

[N2][H2]3


. [NH3]_

[N2][H2]3


[NH3]2

[N2][H2]


[NH3]2

[N2][3H2]3

Respuesta :

anfabba15

Answer:

First option:

[NH3]2  / [N2][H2]3

Explanation:

First of all we need to determine the reaction:

N₂(g) + 3H₂(g) → 2NH₃(g)

1 mol of nitrogen can combine with 3 moles of hydrogen to produce 2 moles of ammonia.

Remember that Kc has to involve Molar concentrations of products / reactants

Concentration must be elevated to the stoichiometry coefficient

Kc for the reaction is:  [NH₃]²  / [N₂] . [H₂]³

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