What is the ratio (in the form of a decimal) of the root-mean-square speed of 238UF6 to that of 235UF6 at constant temperature? Express your answer to three significant figures.

Question

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Respuesta :

ruchi86 ruchi86 · Answer 1 · 2020-03-14T19:11:05+01:00

Answer:

ratio=0.996m/s

Explanation:

[tex]RMS=\sqrt{\frac{3RT}{M} }[/tex]; M= molecular weight of compound;

RMS speed is inversly proportional to the molecular weight hence compound having less molecular weight will have more rms speed value.

[tex]V1 for 238 UF_{6}; M1=238+114=352g/mole[/tex]

[tex]V1 for 235 UF_{6}; M1=238+114=352g/mole[/tex]

[tex]V1=\sqrt{\frac{3RT}{352} }[/tex];

[tex]V2=\sqrt{\frac{3RT}{349} }[/tex];

[tex]\frac{V1}{V2}[/tex]=ratio of [tex]238UF_{6} F6 to 235UF_{6}[/tex]=[tex]\sqrt{\frac{349}{352} }[/tex];

[tex]\frac{V1}{V2} =0.9957m/s;[/tex]

[tex]\frac{V1}{V2} =0.996m/s;[/tex]

adioabiola adioabiola · Answer 2 · 2022-01-20T09:43:58+01:00

The ratio (in the form of a decimal) of the root-mean-square speed of 238UF6 to that of 235UF6 at constant temperature is; 0.996.

According to the question;

By the formula for root mean square speed;

Root mean square speed is inversely proportional to the square root of the molar mass as evident in;

[tex]v = \sqrt{ \frac{3rt}{m} } [/tex]

Therefore, the required ratio;

[tex] \frac{ {v}^{1} }{ {v}^{2} } = \sqrt{ \frac{m2}{m1} } [/tex]

Therefore;