Irina ate some candies on Monday. On Tuesday, she ate twice as many candies as she did on Monday. On Wednesday, she ate a third as many candies as she did on Tuesday. On Thursday, she ate five more candies than she did on Wednesday. On Friday, she ate two fewer candies than she did on Thursday. If she ate the same number of candies on Friday as she did on Monday, how many did she eat on Tuesday?

Respuesta :

Answer:

10 candies on

Step-by-step explanation:

On Monday, Irina ate some candies. ( let it be [tex]x[/tex] )

On Tuesday, she ate twice as many as she did on Monday, ( [tex]2x[/tex] )

On Wednesday, she ate a third as many as she did on Tuesday means,

[tex]2x\times\frac{1}{3}[/tex] = [tex]\frac{2x}{3}[/tex]

On Thursday, she ate five more than she did on Wednesday means

[tex]\frac{2x}{3} +5[/tex]

On Friday, she ate two fewer candies than she did on Thursday means

[tex]\frac{2x}{3} +5 -2[/tex]

She ate the same number of candies on Friday as she did on Monday which is given means,

[tex]\frac{2x}{3} +5 -2 = x[/tex]

[tex]\frac{2x}{5} +3 = x[/tex]

By subtracting both side by [tex]\frac{2x}{5}[/tex]

[tex]\frac{2x}{5} - \frac{2x}{5} + 3 = x - \frac{2x}{5}[/tex]

[tex]3 = \frac{5x-2x}{5}\\ 3 = \frac{3x}{5}[/tex]

By cross multiplication:

[tex]3\times5 = 3x \\15 = 3x[/tex]

By dividing both sides by 3

[tex]\frac{15}{3} = \frac{3x}{3} \\5 = x[/tex]

On Tuesday, she ate twice as many as she did on Monday, ( [tex]2x[/tex] ) = [tex]2\times5 = 10[/tex]

Therefore, Irina ate 10 candies on Tuesday.