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A 120 V potential difference is applied to a space heater whose resistance is 11.5 Ω when hot. At what rate is electrical energy being transferred to thermal energy?

Respuesta :

adelekeademolu

Answer:

1250 W

Explanation:

The rate of energy transfer is the power of the heater. The power of the heater is given by

[tex]P = IV[/tex]

From Ohm's law, [tex]V =IR[/tex].

Then[tex]I = \dfrac{V}{R}[/tex]

Hence, power can be written as

[tex]P = \dfrac{V}{R}\cdot V = \dfrac{V^2}{R}[/tex]

Using values from the question,

[tex]P = \dfrac{120^2\ \text{ V}^2}{11.5\ \Omega} = 1252.17\ldots\text{ W} \approx 1250 \text{ W}[/tex]

asuwafoh

Answer:

1252.174 W

Explanation:

Power: This can be defined as the rate at which energy is transferred, The S.I unit of Power is Watt(W).

From the question,

P = V²/R..................... Equation 1

Where P = Power = Rate at which electrical energy is being transferred to thermal energy, V = Voltage applied to the space heater, R = Resistance of the space heater,

Given: V = 120 V, R = 11.5 Ω

Substitute into equation 1

P = 120²/11.5

P = 14400/11.5

P = 1252.174 W.

Hence the rate at which electrical energy is being transferred to thermal energy = 1252.174 W

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