Answer:
E.
Explanation:
As we know that Current in both wire will be same but both have different resistance as per
[tex]R_1 = \rho L/A[/tex]
[tex]R_2 =\rho L/4A[/tex] (As the radius is doubled so cross sectional area will become four times).
Hence, [tex]R_1 = 4\times(R_2)[/tex]
therefore, if current is same in both then voltage will be -
[tex]V_1=4\times(V_2)[/tex] (As V proportional to R , i is same in all)
then-
[tex]E_1 = 4(E_2)[/tex] (As E proportional V , r is same in all)
[tex]\Rightarrow E2 = \frac{(E_1)}{4}[/tex](Electric feild in wide wire)
Option E.