Answer:
The number of different ways to deal bridge hands to four players = 53644737765488792839237440000
Step-by-step explanation:
Total number of cards, N = 52
Each of the four players will receive (52/4) = 13 cards.
Each player 1, 2, 3 and 4 will receive
n₁ = 13, n₂ = 13, n₃ = 13, n₄ = 13
Distributing N different & unique objects into k distinguishable boxes such that nᵢ objects are place in box i (where i= 1,2, 3, 4.....k) can be done in
(n!)/(n₁!n₂!n₃!n₄!.....nₖ!)
So, for this problem, the number of different ways to deal bridge hands to four players = (52!)/(13!13!13!13!) = (52!)/(13!)4
= 53644737765488792839237440000
Hope this Helps!!!
