Answer:
1. What was the diameter of the hailstone in inches_5.09_ and in cm___12.92___ and in feet ____0.42___?
2. What was the total volume of the hailstone in cubic inches___68.64___ and cubic feet____0.03____?
3. What was the fall velocity of this hailstone in m/s_____2.584____ and in mph___5.78_____?
Explanation:
1. If the circumference (L) of the stone is 16 inches, then from the following equation
[tex]L = 2\pi R[/tex]
[tex]R = \frac{L}{2\pi} = \frac{16}{2\pi} = 2.54 ~inches[/tex]
[tex]D = 2R = 5.09 ft[/tex]
1 inch = 2.54 cm = 0.08 ft, so 5.09 inches = 12..92 cm = 0.42 ft
2. The total volume is
[tex]V = \frac{4}{3}\pi R^3 = \frac{4}{3}\pi (2.54)^3 = 68.64~in^3\\68.64 ~in^3 = 0.03~ft^3[/tex]
3. The fall velocity is V = kd, where k = 20 if d is in cm. Let's calculate the fall velocity in cm.
[tex]V = 20*12.92 = 258.4~cm/s = 2.584~m/s[/tex]
2.584 m/s = 5.78 mph