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A metal wire is in thermal contact with two heat reservoirs at both of its ends. Reservoir 1 is at a temperature of 781 K, and reservoir 2 is at a temperature of 335 K. Compute the total change in entropy arising from the conduction of 1477 J of heat through the wire. Please give your answer in units of J/K.

Respuesta :

Answer:2.517 J/K

Explanation:

Given

Reservoir 1 Temperature [tex]T_1=781 K[/tex]

Reservoir 2 Temperature [tex]T_2=335 K[/tex]

Let Q is the amount of heat Flows i.e. [tex]Q=1477 J[/tex]

thus change in Entropy is given by [tex]\frac{\sum Q}{T}[/tex]

[tex]\Delta S=\frac{\sum Q}{T}=-\frac{Q}{T_1}+\frac{Q}{T_2}[/tex]

[tex]\Delta S=\frac{\sum Q}{T}=-\frac{1477}{781}+\frac{1477}{335}[/tex]

[tex]\Delta S=\frac{\sum Q}{T}=-1.891+4.4089[/tex]

[tex]\Delta S=\frac{\sum Q}{T}=2.517 J/K[/tex]                              

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