Answer:
Probability of making atleast one hire is 0.94
Step-by-step explanation:
Given data:
Assuming X as random variable
[tex]P(X \geq 2) = 45\%[/tex]
[tex]P(X \geq 0 ) = 6\%[/tex]
[tex]P(X \geq = 3) = 11\%[/tex]
Probability of making atleast one hire
[tex]P(X \geq a) =1 - P(X < a)[/tex]
then
[tex]P(X \geq 1 ) = 1 - P(X < 1)[/tex]
[tex]= 1 - P(X = 0)[/tex]
= 1 - 0.06
=0.94