Answer:
The distance is 15.21 m.
Explanation:
Given that,
Height of bridge h= 100 m
Length = 30 m
Spring constant = 40 N/m
Mass = 80 kg
Suppose we need to find the distance when the cord reaches its maximum elongation
We need to calculate the distance
[tex]D= h+x[/tex]
[tex]D=100+x[/tex]
We need to calculate the gravitational potential energy
Using formula of gravitational potential energy
[tex]P.E_{i}=mgh[/tex]
Put the value into the formula
[tex]P.E=80\times9.8\times h[/tex]
[tex]P.E=784h[/tex]....(I)
We need to calculate the elastic energy in cord
Using formula of elastic energy in cord
[tex]E=\dfrac{1}{2}kx^2[/tex]
[tex]E=\dfrac{1}{2}\times40\times x^2[/tex]
[tex]E=20x^2[/tex].....(II)
We need to calculate the value of x
From equation (I) and (II)
[tex]784h=20x^2[/tex]
Put the value of h into the formula
[tex]784(100+x)=20x^2[/tex]
[tex]20x^2-784x-78400=0[/tex]
[tex]x=85.21\ m[/tex]
Cord will be extended by 85.21 m when jumper at maximum elongation of the cord.
We need to calculate the distance
[tex]D=100-(30+85.21)[/tex]
[tex]D=-15.21\ m[/tex]
Negative sign shows the distance of under water.
Hence, The distance is 15.21 m.