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Three families went to the fair together. An adult ticket cost $7, and a child ticket cost $5. If they spent a total of $58, how many adults and how many children were there?

Respuesta :

4 adults and 6 children

Step-by-step explanation:

7×4=28, 5×6=30, 28+30=$58

yoodyannapolis

There are 4 adults and 6 children.

Three families went to the fair together.

So, let us consider that there are m adults and n children. Then

Cost of an adult ticket = $7

Cost of a child ticket = $5

Total bill = $58

So, 7m+5n=58

We have to find the positive integral values of m and n.

Now, gcd(7,5)=1 which is divides 58

It means the equation is solvable.

7m+5n=58

So, the value of m and n that satisfies the equation is m=4 and n= 6.

7×4=28, 5×6=30 and 28+30=$58

Therefore there are 4 adults and 6 children.

Learn more:https://brainly.in/question/4285673

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