Respuesta :
Answer:
#code in python.
#function that reverse the element of list
def reverse(inp_lst):
for i in range(len(inp_lst)//2):
inp_lst[i], inp_lst[len(inp_lst) - i - 1] =inp_lst[len(inp_lst) - i - 1], inp_lst[i]
#main method
def main():
#create a list
lst1 = list(range(8))
print("list before revere:",lst1)
#call the method with list parameter
reverse(lst1)
print("list after revere:",lst1)
#create another list
lst2 = list(range(5))
print("list before revere:",lst2)
#call the method with list parameter
reverse(lst2)
print("list after revere:",lst2)
#call the main method
main()
Explanation:
In main method, create a list and call the method revers() with the list parameter. In the revers() method, swap the first element with last and second with second last. Similarly loop will run half the length of list.This will reverse the elements of the list.Then print the list before and after the revers in the main .Similarly we can test it for another list.
As the loop run for n/2 time in the method reverse(), so the complexity of the code is O(n).
Output:
list before revere: [0, 1, 2, 3, 4, 5, 6, 7]
list after revere: [7, 6, 5, 4, 3, 2, 1, 0]
list before revere: [0, 1, 2, 3, 4]
list after revere: [4, 3, 2, 1, 0]
