A student performed the following system to find the solution to the equation x2-2x-8=0
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The student messed up on step one. The proper factoring is (x-4) (x+2)
Answer:
B. in step 1
Step-by-step explanation:
Given that a student performed the following steps to find the solution of the quadratic equation [tex]x^2-2x-8=0[/tex].
Step 1: Factor the polynomial into (x-4) and (x-2).
Step 2: x-4=0 and x-2=0
Step 3: x=4 and x=2.
Now we need to find about which step has the error.
let's multiply (x-4) and (x-2)
we get : [tex](x-4)(x-2)=x^2-4x-2x+8=x^2-8x+8[/tex]
While original problem has -8 as the last term. So that means factors are wrong.
Hence choice B. in step 1. is correct