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Answer: The expression is undefined for x=4 and x=5.

The expression is undefined for any x that makes the denominator 0. This leads to solving a quadratic equation:

[tex]\frac{x+3}{x^2-9x+20}\\x^2-9x+20\neq 0\\x_{1,2}\neq\frac{9\pm\sqrt{9^2-80}}{2}=\frac{9\pm1}{2}\\x_1\neq4\\x_2\neq5[/tex]

Answer:

Step-by-step explanation:

Alright, lets get started.

The rational expression is gien as :

[tex]\frac{x+3}{x^2-9x+20}[/tex]

For being the function undefined, the denominator must be equal to zero.

[tex]x^2 -9x +20=0[/tex]

factoring

[tex](x-5)(x-4)=0[/tex]

This will give two values of x, which are

x = 5 and x = 4

So,the answer is 4 and 5.   :   Answer

Hope it will help :)

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