Respuesta :
To solve this we will use the formula q=mc delta T. Q is heat, m is mass, c is specific heat and delta T is change in temperature. because it is a phase change problem, temperature does not apply. Also, we will use heat of fusion of water (344J/g) instead of specific heat. We will also convert 0.400 kJ to J, which becomes 400 J.
0.400 kJ x (1000 J/1 kJ) = 400 J
400 J = (g) x (334 J/g)
g = 1.198
Because of sig figs, we will round to 1.20 grams (3 sig figs). The answer is 1.20 grams.
0.400 kJ x (1000 J/1 kJ) = 400 J
400 J = (g) x (334 J/g)
g = 1.198
Because of sig figs, we will round to 1.20 grams (3 sig figs). The answer is 1.20 grams.
The mass of ice that has been melted by 0.400 kJ of heat has been 1.16 grams.
The heat of fusion has been the amount of heat required to change 1 gram of solid to liquid at constant temperature. The heat of fusion of water has been 344 J/gram.
The conversion of ice to water constant temperature has been given by:
Heat = mass × heat of fusion × change in temperature
Since, there has been no change in temperature, the unit has been constant.
Thus, 0.400 kJ of heat has been capable of melting:
0.400 × 1000 J = mass × 344 J/g
400 J = mass × 344 J/g
Mass of ice = [tex]\rm \dfrac{400\;J}{344\;J/g}[/tex]
Mass of ice = 1.16 grams.
The mass of ice that has been melted by 0.400 kJ of heat has been 1.16 grams.
For more information about the melting of ice, refer to the link:
https://brainly.com/question/13699454
