Answer : The mass of chlorine required are, 213 grams
Explanation : Given,
Moles of aluminum chloride = 2 moles
Molar mass of [tex]Cl_2[/tex] = 71 g/mole
The balanced chemical reaction of the formation of aluminum chloride will be,
[tex]2Al+3Cl_2\rightarrow 2AlCl_3[/tex]
From the balanced chemical reaction, we conclude that
As, 2 moles of aluminium chloride obtained from 3 moles of chlorine
So, 2 moles of aluminium chloride obtained from [tex]\frac{3}{2}\times 2=3mole[/tex] of chlorine
Now we have to calculate the mass of chlorine.
[tex]\text{Mass of }Cl_2=\text{Moles of }Cl_2\times \text{Molar mass of }Cl_2[/tex]
[tex]\text{Mass of }Cl_2=3mole\times 71g/mole=213g[/tex]
Therefore, the mass of chlorine required are, 213 grams
